The volume of a 4" square box with depth of 11/2" can accommodate how many conductors of specified gauges?

To determine how many conductors of specified gauges can be accommodated in a box, you first need to calculate the volume of the box. The dimensions of the box are given as 4 inches in width, 4 inches in length, and 1.5 inches in depth.

The volume is calculated using the formula for the volume of a rectangular prism:

Volume = Length × Width × Depth.

Substituting the dimensions:

Volume = 4 in × 4 in × 1.5 in = 24 cubic inches.

Next, the National Electrical Code (NEC) provides volume allowances for conductors based on their gauge. For example, a common allowance for one conductor is often specified as occupying 2 cubic inches for nonmetallic sheathed cables. The exact volume can change based on the type of conductor or if it is part of a cable assembly.

Assuming the people taking this test are working with conductors that require a specific volume, let’s say they require 3 cubic inches for larger gauge conductors, or 2 cubic inches for smaller ones. For a box of 24 cubic inches:

If the conductors require 3 cubic inches each, the calculation would be:

24 cubic inches / 3 cubic inches